200-125 Guide

200-125 Exam Royal Pack (In Stock.)

 
  • Cisco
  • Exam Number/Code 200-125
  • Product Name CCNA Cisco Certified Network Associate CCNA (v3.0)
  • Questions and Answers
  • 726 Q&As
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New Cisco 200-125 Exam Dumps Collection (Question 1 - Question 10)

Q1. Refer to the exhibit.

A network administrator is adding two new hosts to SwitchA. Which three values could be used for the configuration of these hosts? (Choose three.)

A. host A IP address: 192.168.1.79

B. host A IP address: 192.168.1.64

C. host A default gateway: 192.168.1.78

D. host B IP address: 192.168.1.128

E. host B default gateway: 192.168.1.129

F. host B IP address: 192.168.1.190

Answer: A,C,F

Explanation:

Itu2019s a u201crouter-on-a-sticku201d configuration. Which means each host in the VLAN must corresponds with the VLAN configured on the sub-interfaces.

VLAN 10 is configured on fa0/0.10 and VLAN 20 on fa0/0.20. So each hosts in VLAN 10 must use fa0/0.10 IP address as their default gateway, each hosts must also be in the same subnet as fa0/0.10 IP u2013 same with hosts in VLAN 20.

So find out the usable IP addresses on each sub-interfaces u2013 for 192.168.1.78 /27: 192.168.1.65 u2013 .94 and for 192.168.1.130 /26: 192.168.1.128 u2013 .190.

Host A (using port 6 u2013 VLAN 10) must use IP 192.168.1.79, default gateway 192.168.1.78. Host B (using port 9 u2013 VLAN 20) must use IP 192.168.1.190, default gateway 192.168.1.130.



Q2. What are three components that comprise the SNMP framework? (Choose three.)

A. MIB

B. agent

C. set

D. AES

E. supervisor

F. manager

Answer: A,B,F

Explanation:

The SNMP framework consists of three parts:

u2022An SNMP manager u2014 The system used to control and monitor the activities of network devices using SNMP.

u2022An SNMP agent u2014 The software component within the managed device that maintains the data for the device and reports these data, as needed, to managing systems. Cisco Nexus 1000V supports the agent and MIB. To enable the SNMP agent, you must define the relationship between the manager and the agent.

u2022A managed information base (MIB) u2014 The collection of managed objects on the SNMP agent.

SNMP is defined in RFCs 3411 to 3418.

Reference: http://www.cisco.com/c/en/us/td/docs/switches/datacenter/nexus1000/sw/4_0_4_s_v_1_3/s

ystem_management/configuration/guide/n1000v_system/n1000v_system_10snmp.html



Q3. Which protocol can cause overload on a CPU of a managed device?

A. Netflow

B. WCCP

C. IP SLA

D. SNMP

Answer: D

Explanation:

Sometimes, messages like this might appear in the router console:

%SNMP-3-CPUHOG: Processing [chars] of [chars]

They mean that the SNMP agent on the device has taken too much time to process a request.

You can determine the cause of high CPU use in a router by using the output of the show process cpu command.

Note: A managed device is a part of the network that requires some form of monitoring and management (routers, switches, servers, workstations, printersu2026).



Q4. Scenario

Refer to the topology. Your company has connected the routers R1, R2, and R3 with serial links. R2 and R3 are connected to the switches SW1 and SW2, respectively. SW1 and SW2 are also connected to the routers R4 and R5.

The EIGRP routing protocol is configured.

You are required to troubleshoot and resolve the EIGRP issues between the various routers.

Use the appropriate show commands to troubleshoot the issues.

The loopback interfaces on R4 with the IP addresses of 10.4.4.4/32, 10.4.4.5/32, and 10.4.4.6/32 are not appearing in the routing table of R5. Why are the interfaces missing?

A. The interfaces are shutdown, so they are not being advertised.

B. R4 has been incorrectly configured to be in another AS, so it does not peer with R5.

C. Automatic summarization is enabled, so only the 10.0.0.0 network is displayed.

D. The loopback addresses haven't been advertised, and the network command is missing on R4.

Answer: B

Explanation:

For an EIGRP neighbor to form, the following must match:

- Neighbors must be in the same subnet

- K values

- AS numbers

- Authentication method and key strings

Here, we see that R4 is configured for EIGRP AS 2, when it should be AS 1.



Q5. Which item represents the standard IP ACL?

A. access-list 110 permit ip any any

B. access-list 50 deny 192.168.1.1 0.0.0.255

C. access list 101 deny tcp any host 192.168.1.1

D. access-list 2500 deny tcp any host 192.168.1.1 eq 22

Answer: B

Explanation:

The standard access lists are ranged from 1 to 99 and from 1300 to 1999 so only access list 50 is a standard access list.



Q6. Refer to the exhibit.

If the devices produced the given output, what is the cause of the EtherChannel problem?

A. SW1's Fa0/1 interface is administratively shut down.

B. There is an encapsulation mismatch between SW1's Fa0/1 and SW2's Fa0/1 interfaces.

C. There is an MTU mismatch between SW1's Fa0/1 and SW2's Fa0/1 interfaces.

D. There is a speed mismatch between SW1's Fa0/1 and SW2's Fa0/1 interfaces.

Answer: D

Explanation:

You must configure all interfaces in an EtherChannel to operate at the same speeds and duplex modes. Based on the output shown, SW1 is configured to run at 10Mb while SW2 is operating at 100 Mb.



Q7. CORRECT TEXTCentral Florida Widgets recently installed a new router in their office. Complete the network installation by performing the initial router configurations and configuring R1PV2 routing using the router command line interface (CLI) on the RC.

Configure the router per the following requirements: Name of the router is R2

Enable. secret password is cisco

The password to access user EXEC mode using the console is cisco2 The password to allow telnet access to the router is cisco3

IPV4 addresses must be configured as follows:

Ethernet network 209.165.201.0/27 - router has fourth assignable host address in subnet Serial network is 192.0.2.176/28 - router has last assignable host address in the subnet. Interfaces should be enabled.

Router protocol is RIPV2

Attention:

In practical examinations, please note the following, the actual information will prevail.

1. Name or the router is xxx

2. Enable. secret password is xxx

3. Password In access user EXEC mode using the console is xxx

4. The password to allow telnet access to the router is xxx

5. IP information

Answer:

Router>enable

Router#config terminal

Router(config)#hostname R2

R2(config)#enable secret Cisco 1

R2(config)#line console 0

R2(config-line)#password Cisco 2

R2(config-line)#exit R2(config)#line vty 0 4

R2(config-line)#password Cisco 3

R2(config-line)#login

R2(config-line)#exit R2(config)#interface faO/0

R2(config-if)#ip address 209.165.201.4 255.255.255.224

R2(config)#interface s0/0/0

R2(config-if)#ip address 192.0.2.190 255.255.255.240

R2(config-if)#no shutdown

R2(config-if)#exit R2(config)#router rip

R2(config-router)#version 2

R2(config-router)#network 209.165.201.0

R2(config-router)#network 192.0.2.176

R2(config-router)#end

R2#copy run start



Q8. CORRECT TEXTCCNA.com has a small network that is using EIGRP as its IGP. All routers should be running an EIGRP AS number of 12. Router MGT is also running static routing to the ISP.

CCNA.com has recently added the ENG router. Currently, the ENG router does not have connectivity to the ISP router. All over interconnectivity and Internet access for the existing locations of the company are working properly.

The taskis to identify the fault(s) and correct the router configuration(s) to provide full connectivity between the routers.

Access to the router CLI can be gained by clicking on the appropriate host.

All passwords on all routers arecisco.

IP addresses are listed in the chart below.

MGT

Fa0/0 u2013 192.168.77.33

S1/0 u2013 198.0.18.6

S0/0 u2013 192.168.27.9

S0/1 u2013 192.168.50.21

ENG

Fa0/0 u2013 192.168.77.34

Fa1/0 u2013 192.168.12.17

Fa0/1 u2013 192.168.12.1

Parts1

Fa0/0 u2013 192.168.12.33

Fa0/1 u2013 192.168.12.49

S0/0 u2013 192.168.27.10

Parts2

Fa0/0 u2013 192.168.12.65

Fa0/1 u2013 192.168.12.81

S0/1 u2013 192.168.50.22

Answer:

On the MGT Router: Config t

Router eigrp 12

Network 192.168.77.0



Q9. How many bits are contained in each field of an IPv6 address?

A. 24

B. 4

C. 8

D. 16

Answer: D

Explanation:

An IPv6 address is represented as eight groups of four hexadecimal digits, each group representing 16 bits (two octets). The groups are separated by colons (:). An example of an IPv6 address is 2001:0db8:85a3:0000:0000:8a2e:0370:7334.



Q10. Which two statements describe characteristics of IPv6 unicast addressing? (Choose two.)

A. Global addresses start with 2000::/3.

B. Link-local addresses start with FE00:/12.

C. Link-local addresses start with FF00::/10.

D. There is only one loopback address and it is ::1.

E. If a global address is assigned to an interface, then that is the only allowable address for the interface.

Answer: A,D

Explanation:

Below is the list of common kinds of IPv6 addresses:



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